-3(2x^2-3x)=3

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Solution for -3(2x^2-3x)=3 equation:


Simplifying
-3(2x2 + -3x) = 3

Reorder the terms:
-3(-3x + 2x2) = 3
(-3x * -3 + 2x2 * -3) = 3
(9x + -6x2) = 3

Solving
9x + -6x2 = 3

Solving for variable 'x'.

Reorder the terms:
-3 + 9x + -6x2 = 3 + -3

Combine like terms: 3 + -3 = 0
-3 + 9x + -6x2 = 0

Factor out the Greatest Common Factor (GCF), '3'.
3(-1 + 3x + -2x2) = 0

Factor a trinomial.
3((-1 + x)(1 + -2x)) = 0

Ignore the factor 3.

Subproblem 1

Set the factor '(-1 + x)' equal to zero and attempt to solve: Simplifying -1 + x = 0 Solving -1 + x = 0 Move all terms containing x to the left, all other terms to the right. Add '1' to each side of the equation. -1 + 1 + x = 0 + 1 Combine like terms: -1 + 1 = 0 0 + x = 0 + 1 x = 0 + 1 Combine like terms: 0 + 1 = 1 x = 1 Simplifying x = 1

Subproblem 2

Set the factor '(1 + -2x)' equal to zero and attempt to solve: Simplifying 1 + -2x = 0 Solving 1 + -2x = 0 Move all terms containing x to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -2x = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -2x = 0 + -1 -2x = 0 + -1 Combine like terms: 0 + -1 = -1 -2x = -1 Divide each side by '-2'. x = 0.5 Simplifying x = 0.5

Solution

x = {1, 0.5}

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